Monday, September 19 - Solving Tirgonometric Equations on a SPecified Interval 1

What we did on the Monday class was a review of grade 11, just that we were solving with the 3 Special Triangles :

(they don't want to go in the right place)

How to solve for Ө:

1) Determine the reference angle
2)Select possible quadrant(s) using CAST rule,(Q1 Q2 Q3 Q4)
3)Check the interval given

4)State value(s) for Ө in degrees or radians.

Ex: 2SinӨ=1 interval 0-360

1st step: Solve for SinӨ
(I guess everyone knows how to solve this :P )
SinӨ= 1/2 = O/H (so we know its a 30* angle)

2nd step: draw a diagram (or not/or its given) and look in which quadrant it could be by using CAST rule, here we know it can be in Q1 and Q2 so we gonna get 2 equations

3rd step: calculate Ө in each possible quadrant(s) so Q1=ref. angle(now 30*)
Q2=180* - ref. angle (30*)
so we get the answers of Ө in Q1=30*
and in Q2=150*

Hope it is readable because my english is not so good :) ( in writing something down)

And Good Morning :P