There are many parts to this lesson and they must be done carefully
For example..
sin3Ө=-√2/2
Our first step would be to rationalize √2/2, and we will get -1/2.
Sin = O/H
When we have -,+ 1 as a opposite and 2 as a hypotenues, 45 degrees will be the angle which is π/4.
Sin is negative in Q3 and Q4, that is where the right angle triangles will be placed.
We know that our angle is 45 degrees and its in QIII and QIV, so our next step would be to add π to π/4 and subtract 2π from 5π/4 which equals to 7π/4
Next , we will be adding our [5π/4 + 2kπ, 7π/4+2kπ]
In order for us to get rid of the 3 , we must multiply the denominators by 3.
3Ө= 5π/4x3 + 2kπ/3, 7π/4x3 +2kπ/3
The final answer is
[Ө= 5π/12 + 2kπ/3, 7π/12 +2kπ/3 , where K€I]
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