Friday, September 16 - Special Angles and Trignometric Functions 2

Hi guys its Ishu! On fridays class we started off by going through examples and questions from previous exercises that were assigned for homework and went more in depth with special angles and trigonometric functions. We applied the skills we learned from previous lessons and used them to solve equations. For example:




1st step- Separate everything and figure out the angle that is being referred to. You can also draw out the unit circle for each one if it helps you.

eg. sin(pi/2): (pi/2)=90° aka sin90°
sin(pi/6): (pi/6)=30° aka sin30°
cos(pi/3): (pi/3)= 60° aka cos60°
tan(pi/4): (pi/4)= 45° aka tan45°

2nd step- Make reference to or draw out the quadrantal angles/special triangles for each one and and figure out the exact values.

eg. for sin(pi/2): We'll use our knowledge of quadrantal angles.




By using this diagram, we can figure out that sin (pi/2) = 1 since sin =y and the value for y in P (0,1) is 1.


eg. for sin (pi/6): we know thats the same thing as saying sin of 30°, so we draw the special triangle for 30°, label each side and use SOH to figure out the exact value.




Therefore sin(pi/6) = 1/2 since the opposite side is = 1 and the hypotenuse is = 2.

You should get:
sin(pi/2)=1
sin(pi/6)=1/2
cos(pi/3)=1/2
tan(pi/4)=1

3rd step: Substitute the equation for the exact values you've found and solve.

= 1 [1/2 + 1/2 ]= 1

Therefore,

1 [1/2 + 1/2] =1
1 [2/2] =1
2/2= 1
1=1

*We know that our answers were right because the left side equaled the right side*

And we've finally solved the problem.. YAY. alright i hope this helped and dont forget to do the homework that was assigned as well as the assignment! See you all on Monday, good luck and enjoy your weekend :) ............and just for kicks, someone wanna do my homework?